gagehays831
gagehays831 gagehays831
  • 04-04-2017
  • Physics
contestada

A 52.0-kilogram skateboarder does a trick on a half-pipe. During the trick, he reaches a speed of 8.90 m/s. The radius of the half-pipe ramp is 3.00 meters. What is the minimum centripetal force necessary to keep the skater on the ramp?

Respuesta :

Аноним Аноним
  • 04-04-2017
Centripetal force = mv²/r = 52 * 8.9² / 3 = 1373 N
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kenndrick52
kenndrick52 kenndrick52
  • 07-11-2018

The answer to the question is 1,373

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