t1o2n3i4e5
t1o2n3i4e5 t1o2n3i4e5
  • 01-09-2021
  • Mathematics
contestada

Can someone please solve this for me

Can someone please solve this for me class=

Respuesta :

jwu4444 jwu4444
  • 01-09-2021

Answer:

m<JKD = 22 degrees

Step-by-step explanation:

21x + 5 + 4x + 2 = 132

25x + 7 = 132

25x = 125

x = 5

m<JKD = 4x + 2

4(5) + 2

20 + 2

22

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manishchalise1234 manishchalise1234
  • 01-09-2021
Ghhoggliidtttuyryuduyuyiwuuvvkh I just wanted to let
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