1096175
1096175 1096175
  • 02-08-2020
  • Mathematics
contestada

Simplify $\dfrac{1}{\sqrt2+1}+\dfrac{1}{\sqrt2-1}.$[tex]Simplify $\dfrac{1}{\sqrt2+1}+\dfrac{1}{\sqrt2-1}.$[/tex]

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mathmate
mathmate mathmate
  • 02-08-2020

Answer:

Step-by-step explanation:

common denominator

[tex](\sqrt(2)+1)(\sqrt(2)-1) = (\sqrt{2})^2-1^{2}=2-1 = 1[/tex]

Add with common denominator

[tex]\dfrac{1}{\sqrt2+1}+\dfrac{1}{\sqrt2-1}.[/tex]

[tex]= \frac{{\sqrt2-1}}{1} + \frac{\sqrt2+1}{1}[/tex]

[tex]=2* (\sqrt2)[/tex]

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