cely805 cely805
  • 02-07-2020
  • Mathematics
contestada

Divide: (y2−4y+6)÷(y+1).

Respuesta :

Alfpfeu
Alfpfeu Alfpfeu
  • 02-07-2020

Answer:

Step-by-step explanation:

hello

[tex]y^2-4y+6= (y+1)^2-2y-1-4y+6=(y+1)^2-6y+5=(y+1)^2-6(y+1)+11[/tex]

so

[tex]\dfrac{y^2-4y+6}{y+1}=y+1-6+\dfrac{11}{y+1}=y-5+\dfrac{11}{y+1}[/tex]

hope this helps

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