adipalmer adipalmer
  • 01-11-2019
  • Mathematics
contestada

Show that in a quadrilateral ABCD, AB+BC+CD+DA<2(BD+AC)

Respuesta :

Rishi2005
Rishi2005 Rishi2005
  • 01-11-2019

Step-by-step explanation:

We know that the length of the diagonals will be more than the side.

Lets suppose the quadrilateral is a rectangle, with sides 6 and 4.

The length of a diagonal is:

√(6*6)+(4*4)

√36+16

√52

7.21(rounded off to 3 sig. fig.)

So, 6+4+6+4<2(7.21+7.21)

20< 2*14.42

20<28.84, which is true.

:)

Answer Link

Otras preguntas

How is finding the surface area of a sphere different from finding the surface area of a cone or cylinder?
f(x) = 11x³ - 6x² + x + 3
im having math trouble please help​
How is the legacy of the Cold War impact the US or world today?
Solve for X. 4x2 – 48x +144 = 0
Estimate the perimeter of the figure to the nearest whole number.
2 Points In the late 1980s, what measures did the Soviet government take to improve the country's stability? O A. It tried to make the government more open to t
Doctors check your blood pressure to make sure you re healthy, what other criteria does a doctor use for evaluating your health? "think about what your doctor
I need help and thank you
To what extent are nationalism and ultranationalism, expressions of the pursuit of national interests?