CalebFreezer1696 CalebFreezer1696
  • 03-10-2018
  • Mathematics
contestada

Evaluate:

8C6
A.
28
B.
48
C.
56
D.
112

Respuesta :

gmany
gmany gmany
  • 03-10-2018

[tex]C^n_m=\left(\begin{array}{ccc}m\\n\end{array}\right)=\dfrac{m!}{n!(m-n)!}\\\\C^6_8=\left(\begin{array}{ccc}8\\6\end{array}\right)=\dfrac{8!}{6!(8-6)!}=\dfrac{6!\cdot7\cdot8}{6!\cdot2!}=\dfrac{7\cdot8}{1\cdot2}=\dfrac{56}{2}=28[/tex]

Answer Link
Jadepchavez
Jadepchavez Jadepchavez
  • 02-06-2022

Answer:

28 because I have done this

Step-by-step explanation:

Answer Link

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